1. Berapa pH larutan yang terjadi jika dalam 500 mL larutan terdapat 12 gram CH₃COOH dan 8,2 gram CH₃COONa? (Ka=1,8×10⁻⁵)


Mol CH3COOH = 500 . 12 = 6000, mol CH3COONA = 8,2 . V, CH3COOH = CH3COONA, 6000 = 8,2 V, V = 6000/8,2 = 731 ,70732, CH3COOH03b1 =221aKa.M = 1,8X10^-5.6000 = 221a1,08 X 10^-1, pH = -log H, = – log221a1,08 X 10^-1, , kb = 14/5 = 1×10^9, OH =221a1x10^9 . 731,7032, pH = 14 – log OH