*Beserta caranya ya guys , Thanks


1)tan 175di kuadranii, tan175=-tan(180-175)=-tan5=-a, 2)sin275 kuadraniv, sin275=-sin75=-cos5, nahkalaurumus identitas kan tan^2a+1=1/sin^2a, tan^2(5)+1=1/1-cos^2(5), 1-cos^2(5)=1/(a^2+1), cos^2(5)=a^2/(a^2+1), cos5=, jadisin275=-cos5=-
, 3)soalno3ituapa?mungkinsin-545?, kalaubenarberarti=sin175=sin5, nahtan^2(5)+1=1/sin^2(5), sin^2(5)=1/tan^2(5)+1, sin^2(5)=1/a^2+1, sin5=, , semogamenger