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, diket H2082SO2084 = 5 ml : 0,2 M, 2082SO2084 + NaOH —-> Na2082SO2084 + H2082O, H207a = a . Ma, = 2 0,2, = 4 x 10207b\xb9, pH = – log H207a, = – log 4 x 10207b\xb9, = 4 – log 1, pH = 4, jika di tanyakan juga pOH maka, pOH = 14- pH, = 14 – 4, pOH = 10