Mengapa larutan HCL 0,001 m ph = 3, sama larutan CH3COOH 0,1 M ph = 3.


HCL = , H = 0,001 M =1×10^-3 M, CH3COOH = , setiap 1 liter di jadikan100 ml, MOL = m/v = 0,1 / 100 = 0,001, = 0,001 = 1×10^-3 M, H = 1×10^3M, pH CH3COOH= – log 1×10^-3 = 3, pH HCL = – log 1X10^-3 = 3, jadi karena mollaritasnya sama yaitu 1×10^-3M = pH = 3,