suatu larutan mengandung 0,525 gram HOCl tiap liternya. jika harga Ka= 3×10^-8 maka pH larutan adalah………

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OH-=221akw/ka . G, =221a1.10^-14/3.10^-8 . 525.10^-3, =221a1575.10^-9, =39,6.10^-3, pOH= – log OH-, = – log 39,6.10^-3, = 3-log 39,6, pH=14-(3-log39,6), = 11 – log 39,6, ,